Answer:
a. 0.41
b. 0.87
c. 0.13
Explanation:
From the above question:
We are told that:
Probability that Jerry will not show up = 41% = 0.41
Probability that Jerry will show up =
100 - 41 = 59 = 0.59
Probability that Kramer will not show up = 31% = 0.31
Probability that Kramer will show up
= 100 - 31 = 69% = 0.69
Even though Jerry and Kramer know each other, their decisions can be assumed to be independent.
a. What is the probability that both Jerry and Kramer will show up? (Round your answer to 2 decimal places.)
= P(A) × P(B)
= Probability the Jerry will show up × Probability that Kramer will show up
= 0.69 × 0.59
= 0.4071
≈ 2 decimal places = 0.41
b. What is the probability that at least one of them will show up? (Round your answer to 2 decimal places.)
Probability = 1 - the probability that both Jerry and Kramer will not show up
= 1 - (0.41 × 0.31)
= 1 - 0.1271
= 0.8729
Approximately to 2 decimal places = 0.87
c. What is the probability that neither Jerry nor Kramer will show up? (Round your answer to 2 decimal places.)
Probability = Probability the Jerry will not show up × Probability that Kramer will not show up
= 0.41 × 0.31
= 0.1271
To 2 decimal places = 0.13