Question

Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon would then have twice as much as Kande. How much does each one actually have?​

Answer 1

Given parameters;

Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

• Simon has more money than Kande

S > K

• if Simon gave Kande K20, they would have the same amount;

if Simon gives $20, his money will be S - 20 lesser;

When Kande receives $20, his money will increase to K + 20

S - 20 = K + 20 ------ (i)

• While if Kande gave Simon $22, Simon would then have twice as much as Kande;

if Kande gave Simon $22, his money will be K - 22

Simon's money, S + 22;

S + 22 = 2(K - 22) ------ (ii)

Now we have set up two equations, let us solve;

S - 20 = K + 20 ---- i

S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii

So, S - 20 = K + 20

S + 22 = 2K - 44

subtract both equations;

-20 - 22 = (k -2k) + 64

-42 = -k + 64

k = 106

Using equation i, let us find S;

S - 20 = K + 20

S - 20 = 106 + 20

S = 106 + 20 + 20 = 146

Therefore, Kande has $106 and Simon has $146