Answer:
0.33
Explanation:
Given the following :
P(speeding) = p(s) = 0.75
P(being stopped) = p(t)
P(speeding and gets stopped) = p(s n t) = 0.25
Find the probability that he is stopped, given that he is speeding is written as P(t | s) ;
P(t | s) = p(s n t) / p(s)
P(s n t) = 0.25
P(s) = 0.75
Hence,
P(t | s) = 0.25 / 0.75
P(t | s) = 0.33