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Line j has an equation Of y − 6 = 6(x − 4) . Line k , which is parallel to line j , includes the point (2, 2) . What is the equation of line k ? Write the equation in slope-intercept form. Write the numbers in the equation as proper fractions, improper fractions, or integers.

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Answer:

y = 6x-10 or y-2 = 6(x-2)

Explanation:

If two lines are parallel, it means that they have the same slope.

From the question, we are told that line j is parallel to k, this means that line j has the same slope as k.

First we need to determine the skipe of the like j.

Given equation of line j expressed as

y − 6 = 6(x − 4). To get the slope, we will compare the equation with the general equation y = mx+c where m is the slope.

Rewrite the given equation in standard form

y − 6 = 6(x − 4)

y-6 = 6x-24

y = 6x-24+6

y = 6x-18

Comparing this with y = mx+c, m = 6

Hence the slope of line k is also 6.

The equation of line k passing through the point (2,2) is expressed using the formula y-y0 = m(x-x0)

x0 = 2 and y0 = 2

y-2 = 6(x-2)

y-2 = 6x-12

y = 6x-12+2

y = 6x-10

Hence the equation of the line k in slope intercept form is y = 6x-10

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