Question

How many grams of Nacl would you need to prepare 200 ml of a 5 M SOLUTION. ?

Answer 1

To prepare a 200 ml 5 M NaCl solution, you would need 58.44 grams of NaCl.

Step-by-step explanation:

To calculate the mass of NaCl needed to prepare a 5 M solution, we need to use the formula:

mass = volume x concentration x molar mass

First, we convert the volume from milliliters to liters:

200 ml = 0.2 L

Then, we plug in the values into the formula:

mass = 0.2 L x 5 M x 58.44 g/mol (molar mass of NaCl)

mass = 58.44 g

Therefore, you would need 58.44 grams of NaCl to prepare 200 ml of a 5 M solution.

Answer 2

58.44 g of NaCl are needed.

Step-by-step explanation:

Given data:

Mass of NaCl needed = ?

Volume of solution = 200 mL (200/1000 =0.2 L)

Molarity of solution = 5 M

Solution:

We will solve this problem through molarity formula.

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will put the values.

5 M = moles of solute / 0.2 L

Moles of solute = 5 mol/L × 0.2 L

Moles of solute = 1 mol

Mass of sodium chloride:

Mass = number of moles × molar mass

Mass = 1 mol × 58.44 g/mol

Mass = 58.44 g

Thus, 58.44 g of NaCl needed.