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Two cars travel the same distance. The first car travels 40 mph and reaches its destination in t hours.

The second car travels 55 mph and reaches the destination 3 hours earlier. How long does it take the first
car to reach its destination?

User Adrian Pop
by
5.8k points

1 Answer

5 votes

Answer:

The first car reaches its destination at 11 hours

Explanation:

Distance Traveled

The distance X traveled by and object moving at constant speed is given by:

X=v.t

Where v is the speed and t is the time.

We are given some input data. Two cars travel the same distance, let's call it X. The first car travels at 40 mph and reaches its destination in t hours.

We also know the second car travels at 55 mph and reaches the destination 3 hours earlier. The time used by the second car is t-3 hours

The equation for the distance of the first car is

X=40t

The equation for the distance of the second car is

X=55(t-3)

Both distances are the same, thus

40.t=55(t-3)

Operating:

40t=55t-165

Joining like terms:

15t=165

Solving:

t=165/15

t=11 hours

The first car reaches its destination at 11 hours.

User Chris Harcourt
by
5.9k points