Question

Solve an equation with variables on each side.
8+5c =7c -2

Answer 1

`\boxed {c = 5}`

Explanation:

Solve for the value of
`c`:

`8 + 5c = 7c - 2`

-Take
`7c` and subtract it from
`5c`:

`8 + 5c - 7c = 7c - 7c - 2`

`8 - 2c = -2`

-Subtract
`8` to both sides:

`8 - 8 - 2c = -2 - 8`

`-2c = -10`

-Divide both sides by
`-2`:

`(-2c)/(-2) = (-10)/(-2)`

`\boxed {c = 5}`

Therefore, the value of
`c` is
`5`.

Answer 2

5

Explanation:

You have to move all variables to the left side of the equation. It should be

5c-7c=-2-8. Notice how when 7c and 8 get moved over to their designated places, they become a negative. 5c-7c equals to -2c. -2-8 equals to -10. The equation we have now is -2c=-10. 10 divided by 2 is 5 and there ar two negatives which equal a postiive so the answer is 5.