Question

What is the center of a circle with equation (x-4)2 + y2 = 5?

Answer 1

(4,0)

Explanation:

standard equation for a circle is (x−h)^2 +(y−k)^2 =r^2

circle center: h, k with radius: r

(x-(+4)^2 + (y-0)^2 = 5

the center is (4, 0)