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The graph of the linear equetion 3x + 5y - 15 = 0 cuts the y - axis at the point full solution​

User RafaelTSCS
by
5.4k points

1 Answer

5 votes

Answer:

y =
-(3)/(5)x+3

Step-by-step explanation:

3x + 5y - 15 = 0

So we want to get it in the form y = mx + b

Subtract 5y from both sides;

3x - 15 = -5y OR -5y = 3x - 15

Divide both sides by -5

y =
-(3)/(5)x+3

User Collin Krawll
by
4.7k points