Question

What is the equation of a line that passes through (1,2) and is perpendicular to the given line?​

Answer 1

The given line passes through (0,10) and (2,0), so its slope is

`(10-0)/(0-2)=-5`

Since perpendicular lines have negative reciprocal slopes, the slope of the line we want to find is 1/5.

Substituting into point-slope form,

`y-2=(1)/(5)(x-1)\\\\y-2=(1)/(5)x-(1)/(5)\\\\\boxed{y=(1)/(5)x+(9)/(5)}`