Question

Some one explain please

Answer 1

The value of
`x`:

`\boxed {x = (3y)/(4) - 6}`

The value of
`y`:

`\boxed {y = (4x)/(3) + 8}`

Explanation:

Solve for the value of
`x`:

`-4x + 3y = 24`

-Subtract
`3y` to both sides:

`-4x + 3y - 3y = 24 - 3y`

`-4x = 24 - 3y`

-Divide both sides by
`-4`:

`(-4x)/(-4) = (24 - 3y)/(-4)`

`\boxed {x = (3y)/(4) - 6}`

-----------------------------------------------------------------------

Solve for the value of
`y`:

`-4x + 3y = 24`

-Add
`4x` to both sides:

`-4x + 4x + 3y = 24 + 4x`

`3y = 24 + 4x`

-Remember that the equation is in Standard Form:

`3y = 4x + 24`

-Divide both sides by
`3`:

`(3y)/(3) = (4x + 24)/(3)`

`\boxed {y = (4x)/(3) + 8}`