Question

During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed v0 = 38 m/s at an angle θ = 34° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem.

Answer 1

The horizontal distance is 136.6 m.

Step-by-step explanation:

Given that,

Initial speed = 38 m/s

Angle = 34°

Suppose, Calculate the horizontal distance
`x_(max)` in meters the ball has traveled when it returns to ground level.

We need to calculate the horizontal distance

Using formula of range

`R=(v_(0)^2\sin(2\theta))/(g)`

Where, v= speed

g = acceleration due to gravity

Put the value into the formula

`R=((38)^2\sin(2*34))/(9.8)`

`R=136.6\ m`

Hence, The horizontal distance is 136.6 m.