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If h(x) = 32 (x² + 1) -5, what is the value of h(7)? A 167.5 B 170 C 70 D 75​
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If h(x) = 32 (x² + 1) -5, what is the value of h(7)? A 167.5 B 170 C 70 D 75​

If h(x) = 32 (x² + 1) -5, what is the value of h(7)? A 167.5 B 170 C 70 D 75​-example-1
User Carolyn
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Answer:

Explanation:

h(7) = 3.5(7^2 + 1) - 5 = 3.5(49 + 1) - 5= 3.5(50) - 5 = 175-5= 170

answer is b

User WillMonge
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