Question

A rectangle has an area of 4y2 – 49 square

units. What are the dimensions of the
rectangle?

Answer 1

D. (2y - 7) units by (2y + 7) units

Explanation:

• 
  `A(rectangle) =4y^2-49`

• 
  `\implies A(rectangle) =(2y)^2-(7)^2`

• 
  `\implies A(rectangle) =(2y-7)(2y+7)`

• -> D(rectangle) = (2y-7) units by (2y + 7) units