Question

What volume of a 0.25M solution can be prepared with 28.5g of k2s? (molar mass=110.26g)

Answer 1

volume = 1.04 dm^3

Step-by-step explanation:

Data:

volume = ?

Molarity, M = 0.25M

mass = 28.5g

Molar mass = 110.25g

Moles = ?

Solution:

First find number of moles,

moles = mass in gram / molar mass

= 28.5 / 110.25

= 0.258

≈ 0.26 moles

Now,

Molarity =
`(no. of moles)/(volume in dm^3)`

So,

Volume in dm^3 =
`(no. of moles)/(molarity)`

= 0.26 / 0.25

Volume = 1.04 dm^3