Answer:
5, ±√6i
Explanation:
f(x)=x^3-5x^2+6x-30=x^2(x-5)+6(x-5)=(x^2+6)(x-5)
to make f(x)=0, x^2+6=0 or x-5=0
x^2=-6; x=±√6i
x-5=0; x=5
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