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In Exercises 1–4 construct the dual graph for the map shown.

Then find the number of colors needed to color the map so
that no two adjacent regions have the same color.

User Boendal
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1 Answer

8 votes

Answer:

10.8 Graph Coloring

A coloring of a simple graph is the assignment of a color to each vertex of the graph so that no

two adjacent vertices are assigned the same color.

Chromatic number

The chromatic number of a graph is the least number of colors needed for a coloring of this graph.

The Four Color Theorem

The chromatic number of a planar graph is no greater than four.

10.8 pg. 733 # 3

Construct the dual graph for the map shown. Then find the number of colors needed to color the

map so that no two adjacent regions have the same color.

a

b c d e

f

At least three colors are needed to color the

graph because of triangle 4abc exists in the

graph.

10.8 pg. 733 # 7

Find the chromatic number of the given graph.

a

b

c

d

Since this graph forms two triangles, 4abd and

4bcd, we can color this graph with at least 3

colors where a and c are the same colors.

a

b

c

d

10.8 pg. 733 # 9

Find the chromatic number of the given graph.

1

ICS 241: Discrete Mathematics II (Spring 2015)

a

e

b

c

d

This graph can be colored with two colors like

shown.

a

e

b

c

d

10.8 pg. 734 # 19

The mathematics department has six committees, each meeting once a month. How many different

meeting times must be used to ensure that no member is scheduled to attend two meetings at the

same time if the committees are C1 = {Arlinghaus, Brand, Zaslavsky}, C2 = {Brand, Lee, Rosen},

C3 = {Arlinghaus, Rosen, Zaslavsky}, C4 = {Lee, Rosen, Zaslavsky}, C5 = {Arlinghaus, Brand},

and C6 = {Brand, Rosen, Zaslavsky}?

We will first draw the intersection graph of the given sets.

C1 C2

C3

C5 C4

C6

From here, it is easy to see that we need at least 5 colors like so:

C1 C2

C3

C5 C4

C6

Therefore, 5 meeting times are needed. Committees C4 and C5 can meet at the same time.

Step-by-step explanation:

done-_-

User Alan Yong
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