Answer:
Step-by-step explanation:
Volume of bottle filled = 2/3 x π R²h , R = radius = 2.5cm , h = height = 6 cm
= 2/3 x 3.14 x 2.5² x 6 = 78.5 cm³
volume of one squirt = π R² x .025 = 3.14 x 2.5² x .025 = .49 cm³
No of squirt required = 78.5 / .49 = 160.2 = 160
b )
mass of extract = volume x density = 78.5 x 1.135 = 89 gm
c ) mass of one squirt = volume of one squirt x density = .49 x 1.135 = .57 gm