Answer:
The percentage of customer would less likely to purchase next item is 26.2%
So, The nearest option will be (e).
Explanation:
Given that,
The table of information is
Response = Very satisfied, Satisfied, less than fully satisfied and not satisfied
Frequency = 15, 30, 12 and 4
We need to calculate the total frequency
Using given frequency
![Total\ frequency = 15+30+12+4](https://img.qammunity.org/2021/formulas/mathematics/college/dkpt3yk5m5bfjd2smpa9859j64qm90ft0w.png)
![Tota\ frequency = 61](https://img.qammunity.org/2021/formulas/mathematics/college/phlpmqay3oq6qvmgc2qxtlq1yazsen3e6q.png)
We need to calculate the total number of customers less or not fully satisfied
Using given data
![x = 12+4](https://img.qammunity.org/2021/formulas/mathematics/college/k7rwbb7s2ojlaonbx52vh1kulbyhvdyax1.png)
![x=16](https://img.qammunity.org/2021/formulas/mathematics/high-school/z825gvkr7rltixy7d501bd46flsu11ruw0.png)
Where, x = total number
We need to calculate the percentage of customer would less likely to purchase next item
Using formula for percentage
![percentage\ of\ customer=(total\ number\ of\ customer)/(total\ frequency)*100](https://img.qammunity.org/2021/formulas/mathematics/college/9hpuv4ubjw01wqqaok7x5erzlg73712s0a.png)
Put the value into the formula
![percentage\ of\ customer=(16)/(61)*100](https://img.qammunity.org/2021/formulas/mathematics/college/qmbbxzbu5nnwkxbtaxurvpdq4lgs5vpkdx.png)
![percentage\ of\ customer=26.2\%](https://img.qammunity.org/2021/formulas/mathematics/college/p2bpa6704vpqhi3l3t0gxsf5vcfg8aydid.png)
Hence, The percentage of customer would less likely to purchase next item is 26.2%
So, The nearest option will be (e).