Question

Find the zeros of the function. f(x) = 3x^3 - 21x^2 + 36

Answer 1

Explanation:

f(x)=3x3−21x2+36xf(x)=3x3-21x2+36x

Set 3x3−21x2+36x3x3-21x2+36x equal to 00.

3x3−21x2+36x=03x3-21x2+36x=0

by Solving for x

x=0,4,3