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Write the three forms of the line parallel to the line represented by the equation, 8x+3y=11 such that it passes through the point (9, -5).

1 Answer

5 votes

Answer:

  • 8x + 3y = 57
  • y = -8/3x + 19
  • y + 5 = -8/3(x - 9)

Explanation:

Given function

  • 8x+3y=11

Line parallel to the given has the same slope and passes through the point

  • (9, -5)

Determining the equation

  • 8x + 3y = c
  • 8*9 + 3*(-5) = c
  • c=72 - 15
  • c = 57

So the function is in standard form

  • 8x + 3y = 57

Converting to slope-intercept form

  • y = mx + b
  • 3y = -8x + 57
  • y = -8/3x + 573
  • y = -8/3x + 19

Point-slope form, using the given point

  • y - y1 = m(x - x1)
  • y - (-5) = -8/3(x - 9)
  • y + 5 = -8/3(x - 9)

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