Question

The literature value for the density of aluminum is 5.6 g/mL. If an experimenter calculates a value of 5.2g/mL, what is their percent error?

Answer 1

We have the final answer as

7.14 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual density = 5.6 g/mL

error = 5.6 - 5.2 = 0.4

The percentage error is

`P(\%) = (0.4)/(5.6) * 100 \\ = 7.142857...`

We have the final answer as

7.14 %

Hope this helps you