Question

What is the acceleration of a racing car if it’s speed is increased uniformly form 44m/s to 66 m/s over an 11 sec. period.

Answer 1

`a=2\ m/s^2`

Step-by-step explanation:

Given that,

Initial velocity, u = 44 m/s

Final velocity, v = 66 m/s

Time, t = 11 s

Acceleration = rate of change of velocity

`a=(v-u)/(t)\\\\a=(66-44)/(11)\\\\a=2\ m/s^2`

So, the acceleration of the car is
`2\ m/s^2`.