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If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration is -0.29 m/s??
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3 votes
If a train is going 24 m/s and comes to a stop, what is the distance it covers if the acceleration

is -0.29 m/s??

User Gerardo Abdo
by
5.4k points

1 Answer

3 votes

Step-by-step explanation:

u=24

v=0

a=-0.29

s=

v^2=u^2+2as

s=(v^2-u^2)/2a

s=(0-576)/0.58

s=-575.42

User Scheibk
by
4.3k points
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