Question

11. A bicycle with an initial velocity of +6 m/s accelerates at a rate of +2 m/s2 for 3

seconds. What distance does the bicycle travel during this time?
C С
18 m
9 m
27 m
36 m

Answer 1

S=27 m

Step-by-step explanation:

Answer 2

`\huge\boxed{\sf S = 27 m}`

Step-by-step explanation:

Given:

Initial Velocity =
`\sf V_(i)` = 6 m/s

Acceleration = a = 2 m/s²

Time = t = 3 secs

Required:

Distance = S = ?

Formula:

`\sf S = V_(i)t + (1)/(2) at^2` (Second Equation of Motion)

Solution:

S = (6)(3) + 1/2 (2)(3)²

S = 18 + 9

S = 27 m

`\rule[225]{225}{2}`

Hope this helped!

~AnonymousHelper1807