Question

What is the 96th term of -16,-28,-40 hi

Answer 1

Tn = a + (n - 1) d

where a = first term

n = number of the member of the sequence

d = common difference

a = -16

n = 96

d = second term - first term or

third term - second term

= -28 - (-16) = -28 + 16 = -12 or

= -40 - (-28) = -40 + 28 = -12

d = -12

Tn = a + (n - 1) d

= -16 + (96 - 1) -12

= -16 + (95) -12

= -16 + (-1140)

= -16 - 1140 = -1156