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What’s the derivative of y = 1/(2x^5)?

User Thus
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1 Answer

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Answer:


\displaystyle y' = (-5)/(2x^6)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Identify


\displaystyle y = (1)/(2x^5)

Step 2: Differentiate

  1. Rewrite:
    \displaystyle y = (x^(-5))/(2)
  2. Derivative Property [Multiplied Constant]:
    \displaystyle y' = (1)/(2) (d)/(dx)[x^(-5)]
  3. Basic Power Rule:
    \displaystyle y' = (1)/(2)(-5x^(-6))
  4. Simplify:
    \displaystyle y' = (-5)/(2x^6)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Rajomato
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