Final answer:
To find the distance the swan travels before becoming airborne, we apply the kinematic equation to get 51.43 meters. The time taken to reach the takeoff velocity of 6 m/s, with an acceleration of 0.350 m/s², is found to be 17.14 seconds.
Step-by-step explanation:
The student has presented a physics problem that involves calculating distance and time for a swan getting airborne. To solve this, we can use kinematic equations. Specifically, for part (a), we use the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance. For part (b), the equation t = (v - u) / a is used to find the time, where t is the time. Let's solve these step by step:
- First, we find the distance (s) for the swan to become airborne:
- s = (v² - u²) / (2a) = (6.00 m/s)² / (2 x 0.350 m/s²) = 51.43 m.
- Next, we calculate the time (t) it takes for the swan to reach 6.00 m/s:
- t = (v - u) / a = (6.00 m/s - 0 m/s) / 0.350 m/s² = 17.14 s.
Therefore, the swan travels 51.43 meters before becoming airborne, and it takes 17.14 seconds to reach this velocity and become airborne.