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Find the real solutions of the equation involving fractional exponents: (x+3)^3/2 −8=0
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Find the real solutions of the equation involving fractional exponents: (x+3)^3/2 −8=0

User Iluwatar
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1 Answer

4 votes

Answer:


\boxed{x=1}

Explanation:


(x+3)^{(3)/(2)}-8=0


(x+3)^{(3)/(2)}=8


(x+3)^{(3)/(2) \cdot 2}=8^2


(x+3)^(3)=64


x+3=\sqrt[3]{64}


x+3=\sqrt[3]{4^3}


x+3=4


x=1

User RH Becker
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