Question

It is urgent !!!!

what is the specific heat of a substance that took 5000 j to change 20 k and has a mass or 3 kg?

Answer 1

h=5000j

change in temperature=20k

m=3kg

using C=H÷M×Change in temperature

C=5000÷3×20

C=5000÷60

C=83.33jkg-1k-1