Answer:
5 m/s²
Step-by-step explanation:
From the question given above, it took 8 s for the train to get to a speed of 45 m/s. This simply means the train was maintaining 5 m/s as it travels in order to get to an open track.
Thus, we obtained the following data from the question.
Initial velocity (u) = 5 m/s
Final velocity (v) = 45 m/s
Time (t) = 8 s
Acceleration (a) =.?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it can be expressed as:
a = (v – u) /t
Where:
a is the acceleration.
v is the final velocity.
u is the initial velocity.
t is the time.
With the above formula, we can obtain the velocity of the train as follow:
Initial velocity (u) = 5 m/s
Final velocity (v) = 45 m/s
Time (t) = 8 s
Acceleration (a) =.?
a = (v – u) /t
a = (45 – 5) / 8
a = 40/8
a = 5 m/s²
Therefore, the acceleration of the train is 5 m/s².