Question

Question 1

4.52 moles of Propane in a canister has a volume of 21.0 L and a temperature of 298.0 K what is the pressure in kPa? kPa

R=8.31 L * KPa/mole * K

Round your final answer to the nearest 10th (one decimal point)

Question 2
What is the temperature, in K, of 1.60 mol of hydrogen gas that has a volume of 42.58 liters under 950.2 mmHg of pressure? K

R=8.31 L * KPa/mole * K

101.3 KPa = 760.0 mmHg

Round your final answer to the nearest 10th (one digit after the decimal point).

Answer 1

(1). The pressure is 533 KPa.

(2). The temperature is 406 K.

Step-by-step explanation:

Given that,

Number of moles = 4.52 moles

Volume = 21.0 L

Temperature = 298 K

(1). We need to calculate the pressure

Using ideal equation of gas

`PV=nRT`

`P=(nRT)/(V)`

Where, T = temperature

R = gas constant

V = volume

n = number of moles

Put the value into the formula

`P=(4.52*8.31*298)/(21.0)`

`P=533.0\ KPa`

(2). Number of moles = 1.60 moles

Volume = 21.0 L

Temperature = 298 K

We need to calculate the temperature

Using ideal equation of gas

`PV=nRT`

`T=(PV)/(nR)`

Put the value into the formula

`T=(126.68293*42.58)/(1.60*8.31)`

`T=406\ K`

Hence, (1). The pressure is 533 KPa.

(2). The temperature is 406 K.