Question

The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?

Answer 1

`||\overrightarrow{v}||\approx14.64`

Explanation:

The magnitude of a vector
`\displaystyle \overrightarrow{v}=\langle x,y\rangle` is
`||\overrightarrow{v}||=√(x^2+y^2)`, which essentially describes the length of the vector itself between the initial and terminal points:

`||\overrightarrow{v}||=√(x^2+y^2)\\\\||\overrightarrow{v}||=√((10.5)^2+(10.2)^2)\\\\||\overrightarrow{v}||=√(110.25+104.04)\\\\||\overrightarrow{v}||=√(214.29)\\\\||\overrightarrow{v}||\approx14.64`