Question

A bullet train traveling at 2.5m/s, takes 30 minutes to get to the station.

What was the train's acceleration in m/s^2?

Answer 1

`a=-0.001388\ m/s^2`

Step-by-step explanation:

Given that,

Initial speed of a train, u = 2.5 m/s

Finally, it reaches the station, v = 0 (at rest)

Time, t = 30 minutes = 1800 s

Acceleration is equal to the rate of change of velocity. So,

`a=(v-u)/(t)\\\\a=(0-2.5)/(1800)\\\\a=-0.001388\ m/s^2`

So, its acceleration is
`0.001388\ m/s^2`.