Answer:
(A) The mean temperature for the second week is 4.86 degrees Celsius.
(B) The mean absolute deviation for the second week is 4.86 degrees Celsius.
(C) The second week had greater variability in high temperature.
Explanation:
We are given that the daily high temperatures, in degrees Celsius, for two weeks were recorded. The first week had a mean high temperature of 8 degrees Celsius and a mean absolute deviation (MAD) of 1 degree Celsius.
Here is a list of the high temperatures, in degrees Celsius, for the second week;
5, 9, 7, 0, 3, 5, 5
(A) The mean temperature for the second week is given by;
Mean =
=
=
= 4.86 degrees Celsius
(B) Mean absolute deviation for the second week is calculated as;
Firstly, subtracting mean from each data value;
| 5 - 4.86 | = 0.14
| 9 - 4.86 | = 4.14
| 7 - 4.86 | = 2.14
| 0 - 4.86 | = 4.86
| 3 - 4.86 | = 1.86
| 5 - 4.86 | = 0.14
| 5 - 4.86 | = 0.14
Now, we will find the mean of these deviations;
Mean absolute deviation =

=
= 1.92 degrees Celsius
(C) The second week had greater variability in high temperature because it's mean absolute deviation is greater than that of first week. And also the mean absolute deviation tells us that on average how far the data values are from the mean.