Question

What is the pH of 0.10 M HNO2 solution? (Ka= 4.0 x 10-4)|

Answer 1

The answer is 2.2

Step-by-step explanation:

Since the above substance is a weak acid it's pH can be found by using the formula

`pH = (1)/(2) ( - log(Ka ) - log(c) )`

where

Ka is the acid dissociation constant

c is the concentration of the acid

From the question

Ka = 4.0 × 10-⁴

c = 0.1 M

So we have

`pH = (1)/(2) ( - log(4.0 * {10}^( - 4) ) - log(0.1) ) \\ = (1)/(2) (3.4 + 1) \\ = (1)/(2)(4.4) \: \: \: \: \: \: \: \:`

We have the final answer as

2.2

Hope this helps you