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Find the equation of a line parallel to y=6x-4 and through point (-2,14)

User Bmelnychuk
by
5.3k points

1 Answer

6 votes

Explanation:

Substitute the slope from original line (3 in this case) into the equation of the line

$ y = \red 3 x + b $

Step 2

Substitute the given point (1, 7) into the x and y values

$ y = \red 3 x + b \\ 7 = \red 3 (1) + b $

Step 3

Solve for b (the y-intercept )

$ \begin{align*} 7 &= 3 (1) + b \\ 7 &= 3 + b \\ -3 & -3 \\ \hline \\ 4 &= b \\ \end{align*} $

Step 4

Substitute this value for 'b' in the slope intercept form equation $ y = 3x + 4 $

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Hope it help you

User Matti
by
5.4k points
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