Question

6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021 L. Calcule la cantidad total de Au (en gramos) existente en los océanos y su valor total en dólares. ( 1 onza = $ 948)

Answer 1

The total amount of Au is $
`2.0*10^(24)`

Step-by-step explanation:

Given that,

Mass of 1.0 ml of Au
`m=4*10^(-2)\ g`

Total volume of water in oceans
`V=1.5*10^(21)\ L`

We need to calculate the volume in ml

Using given volume

`V=1.5*10^(21)*1000\ mL`

`V=1.5*10^(24)\ mL`

We need to calculate the total mass of Au

Using given data

`1\ ml\ volume = 4*10^(-2)\ g`

`1.5*10^(24)\ ml=4*10^(-2)*1.5*10^(24)`

So, The total mass of Au is
`6*10^(22)\ g`

The mass will be in ounce,

`Mass=0.035274*6*10^(22)`

`Mass=2.12*10^(21)\ ounce`

The total amount of the Au Will be

`Total\ amount=2.12*10^(21)*948`

`Total\ amount=2.0*10^(24)`

Hence, The total amount of Au is $
`2.0*10^(24)`