Answer:
B.) 75
Explanation:
Given the following :
median = 120
Q1 = 100
Q3 = 150
minimum = 20
maximum = 270
Maximum length of a whisker =?
The interquartile range (IQR) multiplied by 1.5
The Interquartile range (IQR) :
UPPER QUARTILE (Q3) - LOWER QUARTILE (Q1)
150 - 100 = 50
MAXIMUM WHISKER LENGTH :
1.5 * INTERQUARTILE RANGE
1.5 * IQR
1.5 * 50
= 75