Question

A projectile has an initial velocity of 22 m/s. The projectile has an x-component velocity of 6.8 m/s, and a y-component velocity of 21 m/s. What is the range of the projectile?

Answer 1

Step-by-step explanation:

x-component of velocity = ucos(alpha) =6.8 m/s

y - component of velocity = usin(alpha) = 21 m/s

We know that,

`range = u \cos( \alpha ) * t`

`time \: of \: flight \:(t) = (2u \sin( \alpha ) )/(g)`

`range = (6.8 * 2 * 21)/(9.8) = 29.14 \: m`