Answer: x=3 y=3
Explanation:
Assuming you meant 2x+3y=15 as the first problem. You have to make either both the x’s or both the y’all equal in both equations first. Multiply the second equation by 2 (for x’s) and you’ll get 2x+2y=12. The 2x cancels out so you’re left with 3y=15 and 2y=12. Subtract 2y=12 from 3y=15 and you get y=3.
Repeat to figure out x. Multiple second equation by 3 (for equal y’s) and you get 3x+3y=18. This time the first equation is being subtracted from the second one. (3x+3y=18) - (2x+3y=15). Y’s cancel out and you’re left with (3x=18)-(2x=15. Subtract and you get x=3