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The width of a rectangle is 5 feet less than the length. The perimeter is 62. Find the length and width of the rectangle.

Variables: ___________________________

Model equation: ______________________________

Length of the rectangle: ______________________________

Width of the rectangle: ______________________________

2 Answers

6 votes

Answer:

see below and attached.

Explanation:

Perimeter (P) = 2 L (Length) + 2 W (Width)

where P = 62

W = L - 5

P = 2L + 2W

62 = 2L + 2(L -5)

62 = 2L + 2L - 10

72 = 4L

L = 72/4

L = 18

W = L - 5

W = 18 - 5

W = 15

Variables : P, L, W

Model equation: P = 2L + 2W

Length of the rectangle: 18

Width of the rectangle: 13

The width of a rectangle is 5 feet less than the length. The perimeter is 62. Find-example-1
User Aqib Javed
by
7.0k points
2 votes

Perimeter formula: p = 2(w + l)

The perimeter is 62.

p = 62

The width of a rectangle is 5 feet less than the length.

w = l - 5

Substitute and solve.

62 = 2[(l - 5) + l)]

62 = 2l + 2l - 10

62 = 4l - 10

72 = 4l

18 = l

Substitute and solve for the width

w = 18 - 5

w = 13

Therefore, the length is 18 and the width is 13.

Best of Luck!

User Tinus Tate
by
6.5k points
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