Question

Two identical conducting spheres, one that has an initial charge +Q, the other initially uncharged, are brought into contact. While the spheres are in contact, a positively charged rod is moved close to one sphere, causing a redistribution of the charges on the two spheres so the charge on the sphere closest to the rod has a charge of -Q. What is the charge of the other sphere?

Answer 1

The new charge is
`k = 2 Q`

Step-by-step explanation:

From the question we are told that

The initial charge of the first one is
`+Q`

The charge on the sphere closest to the rod is
`-Q`

Generally at the point the charge was redistributed the charge on each sphere is
`+ (Q)/(2)`

Also from the question we are told that the new charge on one of the sphere is -Q

So this mean that

`( Q)/(2) + (Q)/(2) = -Q + k`

Here k is the charge on the other sphere

=>
`k =  2 Q`