Answer: 0.39
Explanation:
Given the following classification :
Heavy smokers (H) = 10%
Light smokers (L) = 20%
Non smokers (N) = 70%
Given that :
The death rates of the heavy and light smokers were five and three times that of the nonsmokers, respectively
Let probability of death = D
P(D | N) = d
P(D | H) = 5d
P(D | L) = 3d
Hence,
P(D) = [P(H) * P(D | H) + P(L) * P(D | L) + P(N) * P(D | N)]
P(D) = [0.1 * 5d + 0.2 * 3d + 0.7 * d]
P(D) = [0.5d + 0.6d + 0.7d]
P(D) = 1.8d
A randomly selected participant died over the five-year period: calculate the probability that the participant was a nonsmoker.
P(N | D) = [P(N) * P(D | N)] / P(D)
P(N | D) = 0.7d / 1.8d
P(N | D) = 0.3888
= 0.39