Question

A car speeds up from 12.0 M/S to 16.0 M/S in 8.00 S what is the acceleration of the car

Answer 1

We have,

Initial velocity,u = 12 m/s

Final velocity,v = 16 m/s

Time taken,t = 8 s

Now,

`\sf \: a = (v - u)/(t)`

`\bf \implies \: a = (16 - 12)/(8)`

`\bf \implies a = (4)/(8)`

`\bf \implies \: a = 0.5 \: m {s}^( - 2)`