Question

Determine the magnitude of the acceleration experienced by an electron in an electric field of 595 N/C .

Answer 1

The value is
`a =- 1.045 *10^(14) \ m/s^2`

Step-by-step explanation:

Generally electrostatic force is mathematically represented as

`F = q * E`

This force can also be mathematically represented as

`F = ma`

=>
`ma = q E`

Here q is the charge on an electron with the value

=>
`q = -1.60 *10^(-19) \ C`

and m is the mass of the electron with value

`m = 9.11 *10^(-31) \ kg`

Here E is given as E = 595 N/C

So

`9.11 *10^(-31) *  a  =  -1.60 *10^(-19)  * 595`

=>
`a =- 1.045 *10^(14) \ m/s^2`