Question

Find three consecutive odd integers such that the sum of the smallest number and twice the largest number is equal to fifteen more than four times the middle number.

Answer 1

The three consecutive odd integers are: -11, -13 and -15.

Explanation:

Let the smallest number be represented by x. then the three consecutive odd integers are: x, (x + 2) and (x = 4).

The sum of the smallest number and twice the larges number = x + 2(x + 4)

Fifteen more than four times the middle number = 4(x + 2) + 15

So that;

x + 2(x + 4) = 4(x + 2) + 15

x + 2x + 8 = 4x + 8 + 15

3x + 8 = 4x + 23

3x - 4x = 23 - 8

-1x = 15

⇒ x = -15

(x + 2) = (-15 + 2) = -13

(x + 4) = (-15 + 4) = -11

The three consecutive odd integers are: -11, -13 and -15.