Question

How many grams of oxygen are needed to

react with 425 grams of magnesium to

produce 600 grams of magnesium oxide?

I’m

Answer 1

The value is
`M_(o) = 175 g`

Step-by-step explanation:

Generally the reaction between oxygen and magnesium is

`2Mg_{({s})} + O_2_((g)) \to 2MgO_((s))`

Generally from the law of mass conservation in a chemical reaction we have that

`M_(m) + M_(o) = M_(z)`

Here
`M_(m)` is the mass of magnesium

`M_(o)` is the mass of oxygen

`M_(z)` is the mass of magnesium oxide

So

`425+ M_(o) = 600`

=>
`M_(o) = 600 - 425`

=>
`M_(o) = 175 g`