Question

How much energy in joules can the solar panel produce each day if solar cells were 100% efficient and generate 1000 watts of power per square meter of surface. Suppose a 1 square meter panel of solar cells has an efficiency of 30% and receives the equivalent of 6 hours of direct sunlight per day.

Answer 1

The value is
`E = 6480000 J/day`

Explanation:

The power produced per square meter is
`P = 1000 \ W`

The efficiency of a solar cell is
`\eta = 100\%`

The efficiency of 1 square meter panel of solar cells is
`\eta_b = 30\%`

The duration of sunlight received by a one square meter panel of solar cells is t = 6 * 60 *60 = 21600 seconds

Generally the power generated by 1 square meter panel of solar cells is mathematically represented

`P_a = \eta_b * P`

`P_a = 0.3 * 1000`

`P_a = 300`

Generally the Energy produced by 1 square meter panel of solar cells per day is mathematically represented as

`E = P_a * t`

=>
`E =  300 * 21600`

=>
`E =  6480000 J/day`

Answer 2

The solar panel produce 6.48 × 10⁶ J of energy each day.

Explanation:

If the solar cells were 100% efficient and generate 1000 watts of power per square meter

The power generated per square meter will be

`(100)/(100) * 1000 watts/m^(2)`

= 1000 watts/m²

This is the power that would be generated per square meter if the solar cells were 100% efficient.

Now, for a 1 square meter panel of solar cells with an efficiency of 30%, the power generated will be

`(30)/(100) * 1000 watts/m^(2) * 1m^(2)`

= 300 watts

This is the power that would be generated by a 1 square meter panel of solar cells with an efficiency of 30%

Now, to determine the energy in joules (J) that the solar panel produce each day

We can determine the energy from the formula

Energy = Power × time

From the question, the solar cells receives the equivalent of 6 hours of direct sunlight per day, that is

Time = (6 × 60 × 60) secs = 21600 secs

Hence,

Energy = 300 watts × 21600 secs

Energy = 6480000 Joules

Energy = 6.48 × 10⁶ J