Fluorine-21 has a half-life of approximately 5 seconds. what percentage of the original nuclei would remain after 15 seconds

Jimcgh asked Nov 6, 2023

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Jimcgh asked Nov 6, 2023

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10 votes

Answer:

1/8th = 12.5%

Step-by-step explanation:

Three half lives would be 1/2 * 1/2 * 1/2 = 1/8 th of original

StefanH answered Nov 11, 2023

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